6 electric lamps connected in parallel at 100 volt explain how they are connected to operate at 200 volts without spoiling them.find the total current intensity in the circuit if the resistance of each lamp 240 Ohm
To operate the 6 electric lamps at 200 volts without spoiling them, you cannot simply connect them in parallel or series as that would lead to excessive voltage or current flowing through the lamps.
To achieve the desired voltage of 200 volts, you will need to connect the lamps in series. When lamps are connected in series, the total voltage across them is divided equally based on the number of lamps.
So, to arrange the 6 electric lamps in a series circuit, you would connect the positive terminal of one lamp to the negative terminal of the next lamp and so on, until you reach the last lamp. Finally, you would connect the positive terminal of the last lamp to the positive terminal of the power source and the negative terminal of the first lamp to the negative terminal of the power source.
Now, let's calculate the total current intensity in the circuit.
Given:
Voltage across each lamp, V = 100 volts
Resistance of each lamp, R = 240 Ohms
Since the lamps are connected in series, the total resistance of the circuit can be calculated by summing up the resistances of the individual lamps:
Total resistance (R_total) = R + R + R + R + R + R = 6R
Substituting the given resistance value, we get:
R_total = 6 * 240 = 1440 Ohms
Now, let's calculate the total current (I_total) flowing through the circuit using Ohm's Law:
I_total = V / R_total
Substituting the given voltage value, we get:
I_total = 200 / 1440 = 0.1389 Amps (approximately)
Therefore, the total current intensity in the circuit is approximately 0.1389 Amps.