Calculus

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Let f be the function defined by f(x)= x^3 + ax^2 +bx + c and having the following properties.
1. the graph of f has a point of inflection at (0,-2).
2. The average value of f(x) on the closed interval (0,-2) is -3.

Determine the values of a,b and c

  • Calculus - Incomplete -

    f' = 3x^2 + 2ax + b
    f'' = 6x + 2a

    f''(0) = -2, so
    6*0 + 2a = -2
    a = -1

    f = x^3 - x^2 + bx + c


    Hey! (0,-2) is
    a) not a closed interval
    b) not written as [low,hi]

    Watch this space for further correct info.

  • Calculus - PS -

    also, my value for a is bad. I'll fix it when the rest of the correction arrives.

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