Calculate the OH - concentration present in water under the following conditions. Enter your answer in scientific notation.
A)[H3O+] = 9.4 x 10-10 M
B)[H3O+] = 5.5 x 10-3 M
C)[H3O+] = 6.2 x 10-12 M
(H^+)(OH^-) = Kw = 1E-14
To calculate the OH- concentration, we can use the following equation:
[H3O+][OH-] = 1.0 x 10^-14
Where [H3O+] is the concentration of H3O+ ions and [OH-] is the concentration of OH- ions in the solution.
Let's calculate the OH- concentration for each given condition:
A) [H3O+] = 9.4 x 10^-10 M
First, plug the given value into the equation:
(9.4 x 10^-10)([OH-]) = 1.0 x 10^-14
Now, solve for [OH-]:
[OH-] = (1.0 x 10^-14) / (9.4 x 10^-10)
[OH-] ≈ 1.064 x 10^-5 M
So, the OH- concentration in water under condition A is approximately 1.064 x 10^-5 M.
B) [H3O+] = 5.5 x 10^-3 M
Using the same equation:
(5.5 x 10^-3)([OH-]) = 1.0 x 10^-14
Now, solve for [OH-]:
[OH-] = (1.0 x 10^-14) / (5.5 x 10^-3)
[OH-] ≈ 1.818 x 10^-12 M
Therefore, the OH- concentration in water under condition B is approximately 1.818 x 10^-12 M.
C) [H3O+] = 6.2 x 10^-12 M
Using the equation:
(6.2 x 10^-12)([OH-]) = 1.0 x 10^-14
Now, solve for [OH-]:
[OH-] = (1.0 x 10^-14) / (6.2 x 10^-12)
[OH-] ≈ 1.613 x 10^-3 M
Thus, the OH- concentration in water under condition C is approximately 1.613 x 10^-3 M.