Give the formula for the conjugate base of each acid.
a. HSO4-
SO4^2-
b. H3PO4
H3PO4
c. HPO42-
PO4^2-
d. HNO3
NO3^-
You would add H2O to the acid and determine the products from a double reaction. The acid who gives the H+ up is the acid and the one who accepts it is the base. You look over at the products and those are called the conjugates.
Do for example...
1) HSO4- + H2O --> H3O+ + SO4-2
So SO4-2 is conjugates base.
You do that for each of these!:)
The acid on the left has a conjugate base on the right.
H20 is acting as base, and H3O+ conjugate acid.
It's pretty much the opposite.
To determine the formula for the conjugate base of an acid, you need to remove one hydrogen ion (H+) from the acid molecule. Here are the formulas for the conjugate bases of each acid:
a. HSO4-:
The acid is H2SO4. To get the conjugate base, remove one hydrogen ion: HSO4- --> SO4^2-.
b. H3PO4:
The acid is H3PO4. To get the conjugate base, remove one hydrogen ion: H3PO4 --> H2PO4-.
c. HPO42-:
The acid is H2PO4-. To get the conjugate base, remove one hydrogen ion: HPO42- --> PO4^3-.
d. HNO3:
The acid is HNO3. To get the conjugate base, remove one hydrogen ion: HNO3 --> NO3-.
a is right.
b is not
c would be ok if you had the correct charge on PO4^3-
d is ok.