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algebra

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A collection of nickels, dimes, and quarters amounts to $9.50. If there are 130 coins in all and there are twice as many dimes as there are quarters, find the number of nickels.

  • algebra -

    number of quarters --- x
    number of dimes ----- 2x
    number of nickels ----- 130 - x - 2x = 130-3x

    5(130-3x) + 10(2x) + 25x = 950
    650 - 15x + 20x + 25x = 950
    30x = 300
    x = 10
    So there were 100 nickels

    Check:

    so 10 quarters --> $2.50
    20 dimes and ---> $2.00
    100 nickels -----> $5.00 -->total = $9.50

  • algebra -

    :-)

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