The frequency of oscillation of the wave emitted by an FM radio station is 80.9 MHz. Find the period of vibration. Radio waves travel at a speed of light; 3 × 10
8 m/s. Answer in units of ns
002 (part 2 of 2)
Find the wavelength.
Answer in units of m
To find the period of vibration of the wave emitted by the FM radio station, we can use the formula:
Period = 1 / Frequency
The frequency of the wave is given as 80.9 MHz, which is equivalent to 80.9 × 10^6 Hz. Substituting this value into the formula, we get:
Period = 1 / (80.9 × 10^6 Hz)
To find the wavelength of the radio wave, we can use the formula:
Wavelength = Speed of Light / Frequency
The speed of light is given as 3 × 10^8 m/s and the frequency is 80.9 × 10^6 Hz. Substituting these values into the formula, we get:
Wavelength = (3 × 10^8 m/s) / (80.9 × 10^6 Hz)
Now, let's calculate the period and wavelength separately.
1. Period:
Period = 1 / (80.9 × 10^6 Hz)
= 1 / (8.09 × 10^7 Hz)
= 1.235 × 10^(-8) s
Therefore, the period of vibration is approximately 1.235 × 10^(-8) s or 12.35 ns (since 1 ns is equal to 10^(-9) s).
2. Wavelength:
Wavelength = (3 × 10^8 m/s) / (80.9 × 10^6 Hz)
= (3 × 10^8 m/s) / (8.09 × 10^7 Hz)
= (3.706 × 10) m
= 3.706 m
Therefore, the wavelength of the radio wave is approximately 3.706 m.