Physics
posted by Igbekele .
A solid rectangular block measure 0.100*0.080m*0.060m and floats freely in a liquid of density 1354kg/m^2 if the depth of liquid 0.04m up the block largest side. Find the density of the block.

Vr=0.100 * 0.08 * 0.06=4.8*10^4 m^3 =
480 cm^3.
Vb=0.04 * 0.08 * 0.06 = 1.92*10^4 m^3 = 192 cm^3 = Vol. below surface.
Vb = (Dr/Dl)*Vr = 1.92*10^4 m^3.
(Dr/1354)*4.8*10^4 = 1.92*10^4.
Multiply both sides by 1354:
Dr*4.8*10^4 = 2599.68*10*4.
Dr = 541.6 kg/m^3=Density of rectangle.