what is the slope of the line tangent to the curve (/x)^2 at point (4,16)
* (/x)= the squareroot of x
(√x)2 is just x.
The point (4,16) lies on the curve for x2
Wanna take another stab at it?
* (/x)= the squareroot of x
The point (4,16) lies on the curve for x2
Wanna take another stab at it?