college algebra
posted by missy .
Find the maximum or minimum for f(x)=3x^2+x+1

using Calculus ...
f'(x) = 6x + 1
6x+1 = 0
x = 1/6
f(1/6) = 3(1/36)  1/6 + 1 = 11/12
since the parabola opens upwards,
the minimum value is 11/12
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