Ag+2 is generated in a lab. This is an unusual oxidation state for AG. Write the ground state electronic configuration of Ag+2 using the noble gas shortcut.
You can get all of the electron configurations at www.webelements.com. Click on Ag, then scroll down the left side to electron shell properties and find Ag METAL. Then remove the last two electrons.
To write the ground state electronic configuration of Ag+2 using the noble gas shortcut, we first need to determine the number of electrons present in Ag+2.
Silver (Ag) is a transition metal that belongs to the d-block. The atomic number of Ag is 47, meaning its neutral state contains 47 electrons.
To determine the electronic configuration of Ag, we can use the noble gas shortcut. First, we find the noble gas that comes before Ag in the periodic table, which is [Kr] (Krypton), with the electronic configuration 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶.
Since Ag has an atomic number of 47, it means the 5s and 4d orbitals are partially filled in its neutral state. So, the noble gas configuration for Ag is [Kr] 5s² 4d⁹.
Now, Ag+2 means that two electrons have been removed from the neutral Ag atom. So we subtract 2 electrons from the electron configuration: [Kr] 5s² 4d⁹ - 2e⁻ = [Kr] 4d⁷.
Therefore, the ground state electronic configuration of Ag+2, using the noble gas shortcut, is [Kr] 4d⁷.