Trig (Last URGENT)

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sin2x+cosx=0 , [-180,180)
= 2sinxcosx+cosx=0
= cosx(2sinx+1)=0
cosx=0
x1=cos^-1(0)
x1=90
x2=360-90
x2=270

270 doesn't fit in [-180,180) what do I do? Or maybe I did something wrong.

sinx=1/2
x1=sin^-1(1/2)
x1=30
x2=180-30
x2=150

is this correct?

Please and Thank you

  • Trig (Last URGENT) -

    but your domain is from -180 to 180 , so even though 270 will work in the equation , it is beyond your domain.
    But, by looking at the cosine graph , you will see that it also has an x-intercept at x = -90°
    so for your first one,
    x = -90, 0, 90

    the second part for sinx = 1/2
    your answers of 30° or 150° are correct for the given domain.

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