sam spent a total of 5 2/3 hours doing homework. Julia spent 5 5/6 hours doing homework. who spent more time on homework this week? explain
Can't you figure it out from my previous answer?
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To compare the time Sam and Julia spent on homework, we need to find a common unit of measurement. In this case, we can convert both times to the same form, either in fractions or decimals. Let's convert both times to fractions.
Sam spent a total of 5 2/3 hours on homework. We can convert this mixed number to an improper fraction by multiplying the whole number (5) by the denominator (3) and adding it to the numerator (2). The result is 17/3.
Julia spent 5 5/6 hours on homework. To convert this mixed number to an improper fraction, we multiply the whole number (5) by the denominator (6) and add it to the numerator (5). The result is 35/6.
Now that we have both times in fractions, we can compare them directly. We see that Sam spent 17/3 hours, while Julia spent 35/6 hours on homework.
To compare fractions, we can find a common denominator, so we can compare numerators directly. The least common multiple (LCM) of 3 and 6 is 6. So, we can rewrite 17/3 as 34/6 (multiply the numerator and denominator by 2) and compare it to 35/6.
Now it is clear that 35/6 (Julia's time) is greater than 34/6 (Sam's time).
Therefore, Julia spent more time on homework this week than Sam.