State the slope and y intercept for the graph of each equation. y=x+2

Slope=1

Y-intercept=+2

The equation of a straight line is this:

y = mx + b

...where m is the slope and b is the y-intercept.

Look at the format of your equation. Are you able to see the slope and y-intercept?

To find the slope and y-intercept of the equation y = x + 2, we need to compare it with the standard slope-intercept form of an equation: y = mx + b. In this form, m represents the slope, and b represents the y-intercept.

Comparing the given equation, y = x + 2, to the standard form, we can see that the slope (m) is 1 (the coefficient of x), and the y-intercept (b) is 2.

Therefore, the slope of the graph is 1, and the y-intercept is 2.

The y-intercept is the plot on the graph that you get when you set y=0. Substituted into your equation, 0=x+2

Now if you solve for x, you will get the point on the line where it crosses the y-axis, or the point (x,0). Use the equation of a line: y=mx+b where m is the slope and b is the value of y at the y-intercept, to find m (the slope). (hint)The original equation is already in this form y=mx+b, so what is the coefficient of x? That will be your slope

Do you get 1 b/c of the x in front of the x itself? ( imaginary 1)