Vectors
A) 3.5 cm North
B) 4.2 cm West
Algebraically subtract B from A(B-A)
Whaaaa? Please help
B from A is A-B (not B-A)
A-B=3.5N-4.2W
Hi Bob ... the first post is actually the question ..
subtract B from A(B-A)
well if you want to subtract the vector B from "A(B_A)" you have to do some defining what that second term is. To subtract B from it, it has to be a vector, so do you mean the cross product of A and (B-A)? Otherwise, it makes no sense.
First A(B-A) then subtract B again from that answer.
I see A as (0,3.5) and B as (-4.2,0)
I hope that's the right way algebraically.
Sure! To algebraically subtract vector B from vector A (B - A), you need to subtract the corresponding components of vector B from vector A.
In this case, vector A is 3.5 cm North, and vector B is 4.2 cm West. Since North and West are perpendicular directions, we can treat them as separate components.
Let's break down the components of each vector:
Vector A:
- North component: 3.5 cm
- West component: 0 cm
Vector B:
- North component: 0 cm
- West component: 4.2 cm
Now, to algebraically subtract B from A, you subtract the respective components:
(B - A) = (0 - 3.5) cm North + (4.2 - 0) cm West
Simplifying that, you get:
(B - A) = -3.5 cm North + 4.2 cm West
So, the result of algebraically subtracting vector B from vector A is -3.5 cm North + 4.2 cm West.