if one man 50 kgs fell from 10 meter high builder, how much impact force
when he hit the concrete ground and how long the time it happen.
There is no answer to this. Did he bounce?
assume he do not bounce at all
To calculate the impact force and the time it takes for a person to fall and hit the ground, we can use the principles of physics.
1. Impact Force (F):
The impact force can be determined using the equation for gravitational potential energy (PE) and the relationship between force (F), mass (m), and acceleration due to gravity (g).
Potential Energy (PE) = m × g × h
Where:
m = mass (in kg) = 50 kg (given)
g = acceleration due to gravity = 9.8 m/s^2 (approximate value on Earth)
h = height (in meters) = 10 m (given)
PE = 50 kg × 9.8 m/s^2 × 10 m
PE = 4900 Joules
The impact force can be assumed to be the same as the potential energy (PE) because all the potential energy is converted into kinetic energy upon impact. Therefore, the impact force would be 4900 Joules.
2. Time (t):
To calculate the time it takes for the person to fall from a certain height, we can use the equation of motion for free fall:
h = (1/2) × g × t^2
Rearranging the equation for time (t), we get:
t = sqrt((2 × h) / g)
t = sqrt((2 × 10 m) / 9.8 m/s^2)
Calculating the value, t ≈ 1.43 seconds (approximate).
Therefore, the impact force when the person hits the ground would be 4900 Joules, and the time it takes for the person to fall and hit the ground would be approximately 1.43 seconds.