A box contains 5 bags of potato chips, 4 bags of pretzels and 1 bag of corn chips. Andre reaches in the box and randomly picks two bags, one after the other. What is the probability that Andre chooses a bag of potato chips if the first bag was pretzels?

4/32

To find the probability that Andre chooses a bag of potato chips given that the first bag was pretzels, you need to calculate the conditional probability.

First, let's calculate the probability of picking pretzels as the first bag. There are a total of 5+4+1 = 10 bags.

The probability of picking a bag of pretzels as the first bag is 4/10 = 2/5.

After removing one bag of pretzels from the box, there will be 9 bags left, with 4 bags of potato chips remaining.

The probability of picking a bag of potato chips as the second bag, given that the first bag was pretzels, is 4/9.

To find the probability of choosing a bag of potato chips given that the first bag was pretzels, we multiply the probabilities of both events occurring:

(2/5) * (4/9) = 8/45.

Therefore, the probability that Andre chooses a bag of potato chips if the first bag was pretzels is 8/45.

To find the probability that Andre chooses a bag of potato chips if the first bag was pretzels, we first need to determine the number of favorable outcomes and the number of possible outcomes.

Let's analyze the scenario step by step:

Step 1: Determine the number of favorable outcomes.
Since Andre initially picks one bag of pretzels, there are 4 bags of pretzels remaining in the box, while the number of bags of potato chips remains the same (5). Therefore, there are still 5 bags of potato chips that Andre could choose from.

Step 2: Determine the number of possible outcomes.
Before Andre picks any bag, there are a total of 5+4+1 = 10 bags in the box. After Andre picks the first bag, there are only 9 bags left in the box.

Step 3: Calculate the probability.
The probability of choosing a bag of potato chips if the first bag was pretzels can be expressed as:

(Number of favorable outcomes) / (Number of possible outcomes)

In this case, there is 1 favorable outcome (choosing a potato chips bag) and 9 possible outcomes (remaining bags in the box). So the probability is:

1 / 9

Therefore, the probability of Andre choosing a bag of potato chips if the first bag was pretzels is 1/9.