algebra

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How do i solve 8y to the 2nd plus 30y plus 13

  • algebra -

    I assume you mean you want to solve

    8y^2 + 30y + 13 = 0

    You know that if it factors, it will have factors of the form

    (8y+?)(y+)
    or
    (4y+?)(2y+?)
    where ? is either 1 or 13. You also need the inside and outside products to add to 30y.

    (4y+13)(2y+1) does the trick.
    So, y = -13/4 or -1/2

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