Consider an ideal pulley system. Pull one end of a rope downward by 1 meter with 50 N of force, and you'll lift a 200-N load a distance of ____________________.
A) 1 meter.
B) 0.5 meter.
C) 0.25 meter.
D) None of these.
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To solve this problem, we need to apply the principles of an ideal pulley system. In an ideal pulley system, the tension in the rope remains constant, and the force applied on one end of the rope is transmitted equally to the load at the other end.
In this case, the force applied on one end of the rope is 50 N, and the load being lifted is 200 N. Since the tension in the rope is constant, we can set up the equation:
Force applied on one end of the rope = Force on the load
50 N = 200 N
Now, to find the distance the load is lifted, we need to use the equation:
Work done = Force * Distance
Since the work done is the same on both the applied end and the load end, we can write:
Force applied on one end * Distance applied end = Force on the load * Distance load end
50 N * 1 meter = 200 N * Distance load end
Now, let's solve for Distance load end:
Distance load end = (50 N * 1 meter) / 200 N
Distance load end = 0.25 meter
Therefore, the correct answer is C) 0.25 meter.