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AX is the bisector of <BAC p is any point on AX. prove that the perpendicular drawn from Pto AB and AC are equal

  • MATHS -

    let pb and pc be the perpendiculars to AB and AC.

    Since Ax is the angle bisector, angle XAB = XAC

    using similar triangles,

    pb/pa = pc/pa
    so,
    pb=pc

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