math
posted by Bose .
If A varies inversely as the square of B and A=25 when B=1/5.Find B when A=49

If A varies inversely with the square of B,
A*B^2 = constant.
In this case, the constant is
A/B^2 = 25*(1/5)^2 = 1
When A = 49, B = 1/7
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