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If A varies inversely as the square of B and A=25 when B=1/5.Find B when A=49

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    If A varies inversely with the square of B,
    A*B^2 = constant.

    In this case, the constant is
    A/B^2 = 25*(1/5)^2 = 1

    When A = 49, B = 1/7

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