Calculusderivatives
posted by Jessi .
Determine h'(x) for h(x)= [x/(1x)]^2

h(x) = [x/(1x)]^2 = x^2 * (1x)^2
h'(x) = 2x/(1x)^2 +(2)(1)*x^2*(1x)^3
= 2x/(1x)^2 + 2x^2/(1x)^3
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