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the international space station orbits 350 km above earth's surface. earth's radius is about 6370 km.use the pythagorean theorem to find the distance from the space station to earth's horizon.

  • math -

    sqrt[(6370+350)^2 -(6370)^2]
    = 2140 km

    The hypotenuse is 6720 and the radius (6370) from the center to the point of tangency is perpendicular to the earth's surface

  • math -

    let that distance be x

    solve ...

    x^2 + 6370^2 = 6720^2

    ( I got 2140.44)

  • math -

    Yeah so add 20 plus 11 and get 47 , that's the short way , because once you do that , you'll easily get 2140.5 , you welcome.

  • math -

    an equilateral triangle has a perimeter of 120 inches what is the area of the triangle answer in radical form

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