If f(x) = x-1/2x^2 - x -3.Find

(i)f(2)
(ii) x if f(x)= 0
(iii)values of x that are not in the domain of the function

f(x) = (x-1)/(2x^2) - (x-3)

#1.
f(2) = (2-1)/(2*2^2) - (2-3)
f(2) = 1/(8) - (-1)
f(2) = 1/8 + 1
f(2) = 9/8

#2.
f(x) = (x-1)/(2x^2) - (x-3)
0 = (x-1)/(2x^2) - (x-3)
x - 3 = (x-1)/(2x^2)
(2x^2)(x-3) = x - 1
2x^3 - 6x^2 - x + 1 = 0
x = -0.459
x = 0.350
x = 3.11

#3.
domain is all real numbers except zero.