If a specific class in a frequency distribution has class boundaries of 132.5 - 147.5 what are the class limits ?
It is itself a class boundary not a limit.
It could be class limit if it had some gap between the upper limit of one class and the lower limit of the next class.
To find the class limits, we need to determine the lower class limit and the upper class limit.
The lower class limit is the smallest value that can be included in the class interval. In this case, the lower class boundary is 132.5, which means the lower class limit would be slightly smaller. We can calculate this by subtracting half of the class interval from the lower class boundary:
Lower class limit = Class boundary - (Class interval / 2)
= 132.5 - (147.5 - 132.5) / 2
= 132.5 - 15 / 2
= 132.5 - 7.5
= 125
The upper class limit is the largest value that can be included in the class interval. In this case, the upper class boundary is 147.5. Therefore, the upper class limit is simply equal to the upper class boundary.
Upper class limit = Class boundary = 147.5
So, the class limits for the given class boundaries of 132.5 - 147.5 would be 125 - 147.5.
To find the class limits of a specific class in a frequency distribution, you need to determine the lower class limit and upper class limit.
Given the class boundaries of 132.5 - 147.5, the class limits can be calculated as follows:
Lower Class Limit: Subtract half of the class width (difference between the boundaries) from the lower boundary.
Upper Class Limit: Add half of the class width (difference between the boundaries) to the upper boundary.
Class Width = Upper boundary - Lower boundary
In this case,
Class Width = 147.5 - 132.5
= 15
Lower Class Limit = Lower boundary - (Class Width / 2)
= 132.5 - (15 / 2)
= 132.5 - 7.5
= 125
Upper Class Limit = Upper boundary + (Class Width / 2)
= 147.5 + (15 / 2)
= 147.5 + 7.5
= 155
Thus, the class limits for the given class are 125 and 155.