NaBr+H2SO4
Write the balanced net ionic equation.
Br^- + H^+ ==> HBr
To write the balanced net ionic equation for the reaction between NaBr and H2SO4, you'll need to follow a few steps.
Step 1: Write the complete balanced equation.
The first step is to write the complete balanced equation by combining the reactants and predicting the products. In this case, NaBr (sodium bromide) and H2SO4 (sulfuric acid) are the reactants. The reaction can be represented as follows:
NaBr + H2SO4 → NaHSO4 + HBr
Step 2: Split the equation into its ionic forms.
Next, you need to split the balanced equation into its ionic forms, separating the compounds into their individual ions. In this case, NaBr breaks apart into Na+ and Br-, while H2SO4 breaks apart into H+ and SO4^2-.
Na+ + Br- + H+ + SO4^2- → Na+ + HSO4- + H+ + Br-
Step 3: Identify the spectator ions.
To determine the net ionic equation, you must identify the spectator ions, which are ions that appear on both sides of the equation and do not participate in the reaction. In this case, Na+ appears on both sides and is a spectator ion.
H+ + Br- + SO4^2- → HSO4- + H+ + Br-
Step 4: Write the net ionic equation.
The net ionic equation only includes the species that are directly involved in the reaction. In this case, the net ionic equation can be written as:
Br- + H+ + SO4^2- → HSO4- + Br-
Thus, the balanced net ionic equation for the reaction between NaBr and H2SO4 is Br- + H+ + SO4^2- → HSO4- + Br-.