3Ag(s)+4HNO3(aq)-->3AgNO3(aq)+NO(g)+2H2O(l)

Write the new ionic equation.

To write the new ionic equation, we need to break down the given equation into its ionic components. Here's how you can do it:

1. Identify the compounds and their states:
- Ag(s) indicates solid silver.
- HNO3(aq) represents aqueous nitric acid, which dissociates in water.
- AgNO3(aq) represents aqueous silver nitrate, which also dissociates in water.
- NO(g) indicates gaseous nitrogen monoxide.
- H2O(l) represents liquid water.

2. Write the dissociation equations for the compounds that dissociate:
- Ag(s) does not dissociate because it is a solid.
- HNO3(aq) dissociates into H⁺ ions and NO3⁻ ions:
HNO3(aq) → H⁺(aq) + NO3⁻(aq)
- AgNO3(aq) dissociates into Ag⁺ ions and NO3⁻ ions:
AgNO3(aq) → Ag⁺(aq) + NO3⁻(aq)

3. Write the overall ionic equation by combining the dissociation reactions:
3Ag(s) + 4HNO3(aq) → 3AgNO3(aq) + NO(g) + 2H2O(l)

So, the new ionic equation for the given chemical reaction is:
3Ag⁺(aq) + 4H⁺(aq) + 4NO3⁻(aq) → 3AgNO3(aq) + NO(g) + 2H2O(l)

To write the ionic equation, we need to first write the complete equation and then separate it into its ionic components.

The given equation is:
3Ag(s) + 4HNO3(aq) --> 3AgNO3(aq) + NO(g) + 2H2O(l)

Separating the equation into its ionic components, we get:
3Ag(s) + 4H+(aq) + 4NO3-(aq) --> 3Ag+(aq) + 3NO3-(aq) + NO(g) + 2H2O(l)

Therefore, the new ionic equation is:
Ag(s) + H+(aq) + NO3-(aq) --> Ag+(aq) + NO3-(aq) + NO(g) + H2O(l)