posted by Anonymous .
If a chemist has a stock solution of HBr that is 10.0 M and would like to make 450.0 mL of 3.0 M HBr, how would he or she do it?
How many moles do you need in the final solution? That is M x L = x moles
You want that many mols of the stock solution. You know is it 10 M; therefore, 10 M x ?L = x moles.
Solve for ?L.
You may be more comfortable using the dilution formula.
c1v1 = c2v2
v = volume