A physician orders 750mg of chloramphenicol to be added to a 100ml bag of NS. If the drup is reconstituted to 1gm/10ml, how many mills will be added to NS?

To calculate how many milliliters (ml) of chloramphenicol should be added to the bag of normal saline (NS), we first need to find the concentration of chloramphenicol in the given drug reconstitution.

Given information:
- The physician orders 750mg of chloramphenicol.
- The drug is reconstituted to a concentration of 1gm/10ml.

To determine the concentration of the reconstituted drug, convert grams (gm) to milligrams (mg):
1 gm = 1000 mg

Now, divide the total milligrams of chloramphenicol by the concentration of the reconstituted drug:
750 mg / (1 gm/10ml)

To simplify the calculation, we convert grams to milligrams:
750 mg / (1000 mg/10ml)

Divide the milligrams of chloramphenicol by the milligrams of the reconstituted drug:
750 mg / (1000 mg/10ml) = 750 / (1000/10) = 750 / 100 = 7.5 ml.

Therefore, 7.5 milliliters of chloramphenicol should be added to the 100ml bag of NS.