A conducting hollow sphere of radius. 2m and charge 20 micro coulumbs. What is the potential of the sphere at a distance r from the center if:
A)r= .1m?
b)r= .2m?
c) r=.3m?
To find the potential of a conducting hollow sphere at a distance r from the center, you can use the following formula:
V = k * Q / r,
where V is the potential, k is the electrostatic constant (8.99 × 10^9 Nm^2/C^2), Q is the charge of the sphere, and r is the distance from the center.
Let's calculate the potential for each given value of r:
A) r = 0.1 m:
V = (8.99 × 10^9 Nm^2/C^2) * (20 × 10^-6 C) / 0.1 m
= 8.99 × 10^9 Nm^2/C^2 * 0.00002 C / 0.1 m
= 179800 V
Therefore, the potential of the conducting hollow sphere at a distance of 0.1 m from the center is 179800 V.
B) r = 0.2 m:
V = (8.99 × 10^9 Nm^2/C^2) * (20 × 10^-6 C) / 0.2 m
= 8.99 × 10^9 Nm^2/C^2 * 0.00002 C / 0.2 m
= 89900 V
Therefore, the potential of the conducting hollow sphere at a distance of 0.2 m from the center is 89900 V.
C) r = 0.3 m:
V = (8.99 × 10^9 Nm^2/C^2) * (20 × 10^-6 C) / 0.3 m
= 8.99 × 10^9 Nm^2/C^2 * 0.00002 C / 0.3 m
= 59933.3 V
Therefore, the potential of the conducting hollow sphere at a distance of 0.3 m from the center is 59933.3 V.