Dr.Bob222:

I attempted to solve the problem numerous times but keep ending up with the wrong answer. If you would be kind enough to show me the steps I would appreciate it. I'll pose the question once more:
The volume of a gas at 24�C and 0.21 atm is 36 mL. What volume will the same gas sample occupy at standard conditions?

(P1V1/T1) = (P2V2/T2)

(0.21atm*0.036L/297) = (1atm*V/273)
Solve for V. My best guess is that you didn't convert mL to L and you may not have converted 24C to K. I obtained an answer of about 0.0069 or about 6.9 mL.