Post a New Question

algebra

posted by .

A man is 4 times as old as his son.After 16 years he will be only twice as old as his son. find their present ages.

  • algebra -

    The father is 32 and the son is 8. In 16 years the father will be 48 and the son will be 24.

  • maths -

    John is three times as old as Peter .In six years time John will be twice as old as Peter will be.Determine their present ages

  • algebra -

    In 16 years, Ben will be 3 times as old as he is right now.
    How old is he right now?

  • algebra -

    20 60

  • algebra -

    Let the present age of father be x and the son be y.

    Now, x = 4y ---------- (1)

    After 16 years,

    age of father will be x+ 16
    age of son will be y +16

    Therefore, x + 16 = 2( y + 16)
    x + 16 = 2y + 32
    x = 2y + 16
    or 4y = 2y + 16 {Using equation (a)}
    2y = 16
    y = 8

    Plugging back the value of y in equation (1), we get:
    x = 4*8 = 32

    Hence, the present age of father is 32 years and present age of son is 8 years

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question