A man is 4 times as old as his son.After 16 years he will be only twice as old as his son. find their present ages.

The father is 32 and the son is 8. In 16 years the father will be 48 and the son will be 24.

John is three times as old as Peter .In six years time John will be twice as old as Peter will be.Determine their present ages

In 16 years, Ben will be 3 times as old as he is right now.

How old is he right now?

20 60

Let the present age of father be x and the son be y.

Now, x = 4y ---------- (1)

After 16 years,

age of father will be x+ 16
age of son will be y +16

Therefore, x + 16 = 2( y + 16)
x + 16 = 2y + 32
x = 2y + 16
or 4y = 2y + 16 {Using equation (a)}
2y = 16
y = 8

Plugging back the value of y in equation (1), we get:
x = 4*8 = 32

Hence, the present age of father is 32 years and present age of son is 8 years

To find their present ages, let's assign variables. Let the current age of the son be 'S' and the current age of the father be 'F'.

We know that the father is 4 times as old as his son, so we can write the equation: F = 4S.

We're also given that after 16 years the father will be only twice as old as his son. We can express this as: F + 16 = 2(S + 16).

Now we can solve the equations simultaneously to find their ages.

Substitute F = 4S from the first equation into the second equation: 4S + 16 = 2(S + 16).

Expanding the equation, we get: 4S + 16 = 2S + 32.

Combining like terms, we have: 2S = 16.

Dividing both sides by 2, we find: S = 8.

Now substitute the value of S back into the first equation to find F: F = 4(8) = 32.

Therefore, the son's present age is 8 years and the father's present age is 32 years.