# algebra

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A man is 4 times as old as his son.After 16 years he will be only twice as old as his son. find their present ages.

• algebra -

The father is 32 and the son is 8. In 16 years the father will be 48 and the son will be 24.

• maths -

John is three times as old as Peter .In six years time John will be twice as old as Peter will be.Determine their present ages

• algebra -

In 16 years, Ben will be 3 times as old as he is right now.
How old is he right now?

• algebra -

20 60

• algebra -

Let the present age of father be x and the son be y.

Now, x = 4y ---------- (1)

After 16 years,

age of father will be x+ 16
age of son will be y +16

Therefore, x + 16 = 2( y + 16)
x + 16 = 2y + 32
x = 2y + 16
or 4y = 2y + 16 {Using equation (a)}
2y = 16
y = 8

Plugging back the value of y in equation (1), we get:
x = 4*8 = 32

Hence, the present age of father is 32 years and present age of son is 8 years

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