How many moles of oxygen are produced from the decomposition of 3.4g of hydrogen peroxide?
How many molecules of O2 are produced?
write the balanced equation:
2H2O2>>2H2O + O2
how many moles of H2O2 is in 3.4 g?
molesH2O2=3.4/34=.1moles
so with the mole ratio in the balanced equation, you get half that of O2, or .05 moles O2
2H2O2 ==> 2H2O + O2
How many moles do you have in 3.4 g H2O2?
3.4/molar mass H2O2 = approximately 0.1.
You get 1 mol O2 for every 2 mol H2O2.
To convert to molecules, remember that there are 6.02E23 molecules in 1.0 mol.
To determine the number of moles of oxygen produced from the decomposition of hydrogen peroxide, we need to use the balanced chemical equation for the reaction:
2H2O2 → 2H2O + O2
First, let's calculate the number of moles of hydrogen peroxide (H2O2) in 3.4g using its molar mass. The molar mass of H2O2 is:
H = 1.01 g/mol
O = 16.00 g/mol
Molar mass of H2O2 = (2 * 1.01 g/mol) + (2 * 16.00 g/mol) = 34.02 g/mol
Using the formula:
moles = mass / molar mass
moles of H2O2 = 3.4g / 34.02 g/mol ≈ 0.1 mol
From the equation, we see that 2 moles of H2O2 produce 1 mole of O2. Therefore, the number of moles of oxygen produced can be calculated as follows:
moles of O2 = 0.1 mol / 2 = 0.05 moles
To find the number of molecules of O2 produced, we need to use Avogadro's number. Avogadro's number is 6.022 x 10^23 particles per mole.
Number of molecules = moles of O2 * Avogadro's number
Number of molecules = 0.05 mol * 6.022 x 10^23 molecules/mol
Therefore, the number of molecules of O2 produced from the decomposition of 3.4g of hydrogen peroxide is approximately 3.011 x 10^22 molecules.
To determine the number of moles of oxygen produced from the decomposition of hydrogen peroxide, we need to use the balanced chemical equation of the reaction.
The balanced equation for the decomposition of hydrogen peroxide is:
2 H2O2 -> 2 H2O + O2
From the equation, we can see that for every 2 moles of hydrogen peroxide (H2O2), we produce 1 mole of oxygen gas (O2).
To find the number of moles of oxygen produced, we need to convert the given mass of hydrogen peroxide into moles. To do this, we can use the molar mass of hydrogen peroxide, which is 34.0147 g/mol.
First, calculate the number of moles of hydrogen peroxide:
Number of moles = Mass / Molar mass
Number of moles = 3.4 g / 34.0147 g/mol
Number of moles = 0.1 mol
Since the stoichiometry ratio is 2 moles of H2O2 to 1 mole of O2, we can say that 0.1 mole of H2O2 will produce 0.05 moles of O2.
Now, let's calculate the number of molecules of O2 produced.
To convert from moles to molecules, we can use Avogadro's number, which is 6.022 x 10^23 molecules/mol.
Number of molecules = Number of moles * Avogadro's number
Number of molecules = 0.05 mol * (6.022 x 10^23 molecules/mol)
Number of molecules = 3.011 x 10^22 molecules
Therefore, from the decomposition of 3.4 g of hydrogen peroxide, approximately 0.05 moles of oxygen gas (O2) are produced, which is equivalent to 3.011 x 10^22 molecules of O2.