physics

posted by .

A particle is moving clockwise in a circle of radius 1.54 m. At a certain instant, the magnitude of its acceleration is a = 26.0 m/s2,and the acceleration vector has an angle of θ = 50° with the position vector, as shown in the figure. At this instant, find the speed, v of this particle.

  • physics -

    a*sin50=v^2/r solve for v

  • physics -

    not the right answer

  • physics -

    It seems to me that a*cos50 is the centripetal component of the acceleration. The position vector is in the radial direction.

    a*cos50 = v^2/r = 16.71 m/s^2
    v^2 = 25.74 m^2/s^2
    v = 5.07 m/s

  • physics -

    thanks

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. PHYSICS

    When a particle moves on a circle at constant speed, its acceleration vector: a) is zero m/s^2 b) points toward the center of the circle. c) points parallel to its velocity vector. It's zero m/s^2 since it's moving at a constant speed, …
  2. Physics

    A particle is in uniform circular motion about the origin of an xy coordinate system, moving clockwise with a period of 3.50 s. At one instant, its position vector (from the origin) is r = (8.00 m) ihat - (7.00 m) jhat. At that instant, …
  3. physics

    A particle is moving clockwise in a circle of radius 1.75 m. At a certain instant, the magnitude of its acceleration is a = a = 39.0 m/s2, and the acceleration vector has an angle of θ = 50° with the position vector, as shown …
  4. angular momentum

    a 8.20 kg particle P has a position vector of magnitude 6.90 m and angle θ1 = 42.0° and a velocity vector of magnitude 6.70 m/s and angle θ2 = 25.0°. Force , of magnitude 8.90 N and angle θ3 = 28.0° acts on P. All …
  5. physics

    A particle revolves in a horizontal circle of radius 3.20 m. At a particular instant, its acceleration is 1.20 m/s 2 in a direction that makes an angle of 55.0º to its direction of motion. Determine its speed (a) at this moment, and …
  6. Physics (Algerbra-based)

    A particle is moving clockwise around a circle with a radius 3.31 m. The magnitude of the total acceleration of the particle at the given instant is 14.3 m/s^2; the angle between the vector of total acceleration and the radius-vector …
  7. Physics

    The acceleration of a particle moving only on a horizontal xy plane is given by a=5ti+6tj, where a is in meters per second-squared and t is in seconds. At t=0, the position vector r=(19.0m)i+(39.0m)j locates the particle, which then …
  8. Physics

    A particle moves in the xy plane with constant acceleration. At time zero, the particle is at x = 6.0 m, y = 3.0 m, and has velocity v = 4.0 m/s + -1.0 m/s . The acceleration is given by the vector a = 4.0 m/s2 + 0 m/s2 . (a) Find …
  9. Physics I (Classical)

    At some instant, a particle traveling in a horizontal circular path of radius 7.50 m has a total acceleration with a magnitude of 16.0 m/s^2 and a constant tangential acceleration of 12.0 m/s^2. Determine the speed of the particle …
  10. physics

    A particle is traveling counterclockwise in a circle of radius r = 2.30 m. At some instant in time, the particle is located by the angular coordinate α = 24.0°, the total acceleration has a magnitude of a = 15.0 m/s2 and is directed …

More Similar Questions