Pre- Algebra

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Can someone please explain how to do this problem: 7n-5=10n+13

  • Pre- Algebra -

    subtract 7n to the other side
    AND subtract 13 to the other side
    and also divide 3 to the other side,so

    7n-5=10n+13
    -5=10n-7n +13
    -5-13=10n-7n
    -18=3n
    n=-6

  • Pre- Algebra -

    Add 5 to both side
    7n=10n+18
    Then subtract 10n
    -3n=18
    Finally divide -3 on both sides
    n=-6

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