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A projectile is shot at an angle of 40.0 degrees with a velocity of 25.0 m/s. If a building is 50.0 m away, will this projectile strike the building, and if so, at what height?

  • physics -

    The time to reach the building, if it does not hit the ground first, is
    L/(Vo*cos40) = 50/(25 cos40) = 2.61 seconds

    The time to hit the ground, if it does not hit the building first, is
    2 Vo sin40/g = 3.28 s

    Therefore it hits the building (assuming it is tall enough so that the projectile can't go over the top).

    To find out where it hits, use the
    y vs t equation:
    y = Vo*sin40*t - (g/2)t^2
    and use t = 2.61 s

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