Chemistry

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When a 77 g piece of metal with a temperature of 88 Degree Celsius is placed into 277 g of water having a temperature of 20 degree Celsius, the final temperature of the metal and water is 23.3 degree Celsius. What must be the specific heat of the metal?

  • Chemistry -

    heat lost by metal + heat gained by water = 0
    [mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
    Substitute and solve for specific heat metal.

  • Chemistry -

    Thank you bob. However, what is specific heat of a metal is e metal is unknown.

  • Chemistry -

    The problem asks for the specific heat of the metal. That's what you're solving for. Substitute the numbers and solve for specific heat.
    [77 x sp.h.metal x (23.3-20.0)] + [277 x 4.184 x (23.3-20.0)] = 0
    You have only one unknown; i.e., specific heat metal. Solve for that.

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