1-Butene (CH2=CHCH2CH3) burns in the presence of O2 to produce CO2 and H2O. Write the balanced chemical equation for this reaction (omit physical states and use condensed molecular formulas).

CH2CHCH2CH3+6O2=4CO2+4H2O

This is ok but you omitted the double bond in CH2=CHCH2CH3. The double bond needs to be there (even though it's a condensed formula). When it's omitted the observer doesn't know if it is a double bond or if you just forget and left out the two H atoms.

To balance this equation, we need to make sure that there is the same number of atoms of each element on both sides of the equation. Here's how you can balance the equation:

1. Count the number of atoms on each side of the equation:
On the left-hand side (reactant side):
- Carbon (C): 4 atoms
- Hydrogen (H): 8 atoms
- Oxygen (O): 6 atoms

On the right-hand side (product side):
- Carbon (C): 4 atoms
- Hydrogen (H): 8 atoms
- Oxygen (O): 10 atoms (4 from CO2 and 6 from H2O)

2. Adjust the coefficients (numbers in front of molecules) to balance the equation:
- Since there are 4 carbons on both sides, no changes are needed.
- Since there are 8 hydrogens on both sides, no changes are needed.
- However, there are 6 oxygens on the left and 10 on the right. To balance the oxygens, we need to add a coefficient of 5/3 (or 1.67) in front of O2 on the reactant side.

The final balanced equation is:
CH2CHCH2CH3 + (5/3)O2 → 4CO2 + 4H2O