college algebra
posted by jim .
IF THIS WAS 1500 SQFT. WHAT WOULD IT LOOK LIKE.I have two small Yorkies that love to go outside and play, so being on a leash just doesn’t work for them. So I decided to get them a fence so they can play how they like too. I live in a townhouse, its 1600 sqft yet its big enough for them. I will end up needing 165 ft of fencing to keep my dogs safe in my backyard.
2. L=2w+5 and w= 3L4
3. A= LW
1600 sqft= (2W+5)w
1600 sqft= 2W^2 + 5W
2W^2+ 5W 1600 sqft= 0
4. Next I used to the quadratic formula to figure out what w= which is x = +/ sqrt (b^2 – 4ac)/2
W= 5+/ sqrt (5^24(1600)/4
W= 5+/ sqrt (25 + 6400)/4
W= (5+/ 105)/4
W=( 5 + 105)/4
W+ (5 – 105)/ 4
W= 20 ft and w= 27. 5
Length cannot be negative so therefore the w= 27.5
L= 2(27.5) + 5
L= 60 ft
5.) To find the perimeter the formula is P= 2L+2W
P= 2(60) + 2(27.5)
P=110+55
P= 165 ft
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