Theres a circuit wired in series that has 4 resistors.
1) 10 ohms
2) 6 ohms
3) 1 ohms
4) 2 ohms
Find the potential difference across the 10ohm resistor.
Answer in units of V
What exactly am i supposed to do to calculate this?
Oh right, there's a current of 0.1 A
In the circuit below, V = 37 volts, R1 = 3 Ohms, R2 = 4 Ohms, R3 = 10 Ohms, and R4 = 14 Ohms. What is the power output of the battery in Watts?
I'm assuming the resistors are connected
in series.
I = E/(R1+R2+R3+R4) = 37/31 = 1.194A
Po = E*I = 37 * 1.194 = 44.2 Watts
To calculate the potential difference across a resistor in a series circuit, you need to follow these steps:
1. Determine the total resistance of the circuit by adding up the resistances of all the resistors connected in series. In this case, the total resistance will be:
Total Resistance = 10 ohms + 6 ohms + 1 ohm + 2 ohms = 19 ohms
2. Using Ohm's Law, which states that V = I * R, where V is the potential difference (voltage), I is the current, and R is the resistance, we can determine the current flowing through the circuit.
3. Since the circuit is wired in series, the current flowing through all the resistors is the same. So, you need to know the current flowing through the circuit, and you can use this to calculate the potential difference across any resistor.
Unfortunately, you haven't provided any information about the current flowing through the circuit. If you do have the current, you can use Ohm's Law directly to calculate the potential difference across the 10 ohm resistor.
If you have additional information or if you can provide the current value, I can assist you further in calculating the potential difference across the 10 ohm resistor.