AP CHEMISTRY

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If a solution of HF (Ka = 6.8 10-4) has a pH of 3.42, calculate the total concentration of hydrofluoric acid.

  • AP CHEMISTRY -

    pH = 3.42.
    3.42 = -log(H^+)
    (H^+) = 3.80
    E-4
    ...........HF ==> H^+ + F^-
    initial....x.......0.....0
    change.....................
    equil...x-3.8E-4..3.8E-4..3.8E-4

    Ka = (H^+)(F^-)/(HF)
    Substitute from the ICE chart above and solve for x.

  • AP CHEMISTRY -

    no

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