# algebra

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there are 43 ribbions. the number of blue ribbions was 2 less than the number of white ribbions. the number of red ribbions was 3 more than the number of white ribbions.how many of each kind of ribbion was awarded

• algebra -

b = the number of blue ribbions

w = the number of blue ribbions

r = the number of red ribbions

b = w - 2

r = w + 3

w + b + r = 43

w + w - 2 + w + 3 = 43

3 w - 2 + 3 = 43

3 w + 1 = 43

3 w = 43 - 1

3 w = 42 Divide both sides by 3

w = 42 / 3

w = 14

b = w - 2 = 14 - 2 = 12

r = w + 3 = 14 + 3 = 17

14 white ribbons

12 blue ribbons

17 red ribbons

• algebra -

w = the number of WHITE ribbions

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