algebra
posted by Anonymous .
there are 43 ribbions. the number of blue ribbions was 2 less than the number of white ribbions. the number of red ribbions was 3 more than the number of white ribbions.how many of each kind of ribbion was awarded

b = the number of blue ribbions
w = the number of blue ribbions
r = the number of red ribbions
b = w  2
r = w + 3
w + b + r = 43
w + w  2 + w + 3 = 43
3 w  2 + 3 = 43
3 w + 1 = 43
3 w = 43  1
3 w = 42 Divide both sides by 3
w = 42 / 3
w = 14
b = w  2 = 14  2 = 12
r = w + 3 = 14 + 3 = 17
14 white ribbons
12 blue ribbons
17 red ribbons 
w = the number of WHITE ribbions
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