1. Write the equation and balance it.
2. Calculate moles Zn. mol =- g/molar mass
3. Using the coefficients in the balanced equation, convert mols Zn to mols KMnO4.
4. The M KMnO4 = moles KMnO4/L KMnO4.
You knolw M and moles, solve for L and convert to mL.
This is a Quantitative Redox titration. (KMnO4) = 1.8 G.. 500 ML after the experiment we had to record the data of the 3 trials. 1. Trial - VolUme FeSO4 = 10.00 Ml - VOlume KMnO4 11.00 Ml 2. Trial - VolUme FeSO4 = 10.00 ML - VOlume …
A 0.020 M KMnO4 solution was used to determine the percent iron in a sample containing iron(II). MnO− 4 + 5 Fe2+ + 8 H+ → Mn+2 + 5 Fe3+ + 4 H2O It took 25.0 mL of the KMnO4 to completely react with all the iron(II) in the …