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Write the balanced chemical equation for each of these reactions. Include phases. When aqueous sodium hydroxide is added to a solution containing lead(II) nitrate, a solid precipitate forms. However, when additional aqueous hydroxide is added the precipitate redissolves forming a soluble [Pb(OH)4]2–(aq) complex ion.

  • chemistry -

    2NaOH(aq) + Pb(NO3)2(aq) ==> Pb(OH)2(s) + 2NaNO3(aq)

    Pb(OH)2(s) + 2NaOH(aq) ==> Na2Pb(OH)4(aq)

  • chemistry -

    I had the exact same question, but the when I tried the second equation, it was wrong.

  • chemistry -

    Same as Sarah

  • chemistry -

    second equation is

    Pb(OH)2(s)+2OH^-(aq)<---> [Pb(OH)4]^2-(aq)

  • chemistry -

    You forgot the 2Na+(aq) ions as products of the second reaction.

  • chemistry -

    You have to put " Pb(OH)4(aq) " in square brackets... [Pb(OH)4]2–(aq)

  • chemistry -

    The answer for the second equation input is

    Pb(OH)2 (s) + 2 NaOH^- (aq) --> [Pb(OH)4]^2- (aq) + 2 Na^+ (aq)

    This part of the problem annoyed the hell out of me before I actually got it.

  • chemistry -

    Pb(OH)2 (s) + 2NaOH (aq) <--> [Pb(OH)4]^2- + 2Na^+ (aq)

    Don't include the "-" in NaOH

  • chemistry -

    Ole ole Pumas!
    The answer in right

  • chemistry -

    Na2Pb(OH)H(aq)

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