Write the balanced chemical equation for each of these reactions. Include phases. When aqueous sodium hydroxide is added to a solution containing lead(II) nitrate, a solid precipitate forms. However, when additional aqueous hydroxide is added the precipitate redissolves forming a soluble [Pb(OH)4]2–(aq) complex ion.
Pb(OH)2 (s) + 2NaOH (aq) <--> [Pb(OH)4]^2- + 2Na^+ (aq)
Don't include the "-" in NaOH
Not correct on sapling
2NaOH(aq)+Pb(NO3)2(aq)--->Pb(OH)2(s)+2NaNO3(aq)
Pb(OH)2(s)+2OH^-(aq)--->[Pb(OH)4]^2-(aq)
just saw the answer on sapling.
I had the exact same question, but the when I tried the second equation, it was wrong.
The answer for the second equation input is
Pb(OH)2 (s) + 2 NaOH^- (aq) --> [Pb(OH)4]^2- (aq) + 2 Na^+ (aq)
This part of the problem annoyed the hell out of me before I actually got it.
Same as Sarah
Ok, here is the final answer that worked for mines on Sapling
1: 2NaOH(aq) + Pb(NO3)2(aq) --> Pb(OH)2(s) + 2NaNO3(aq)
2: Pb(OH)2(s) + 2OH^-(aq) --> [Pb(OH)4]^2-(aq)
2NaOH(aq) + Pb(NO3)2(aq)-----> Pb(OH)2(s) + 2NaNO3(aq)
**** for Pb(NO3)2 the 2 does not mean to square it you have to put it in the bottom corner as well as Pb(OH)2 the 2 does not mean to square it has to be put in the bottom corner
Pb(OH)2(s) +2OH-(aq)----->[Pb(OH)4]2-(aq)
****for Pb(OH)2 the 2 does not mean to square it you have to put it in the bottom corner
****in [Pb(OH)4]2- the 2- IS SQUARED and the 4 is in the bottom corner