The solubility of cu(io3)2 is 1.0*10-7 what is the solubility of the salt
Solubilitu Cu(IO3)2 = 1.0E-7 whatever unit/whatever volume you used.
To find the solubility of a salt, we need to consider the solubility product constant (Ksp) for the salt. The Ksp is an equilibrium constant that relates to the equilibrium between a solid salt and its dissolved ions in a solution.
In this case, the given solubility of Cu(IO3)2 is 1.0 * 10^{-7}. Let's assume that the salt dissociates completely into copper (Cu2+) ions and iodate (IO3-) ions when in solution.
The formula for Cu(IO3)2 suggests that for every molecule of Cu(IO3)2 that dissolves, one Cu2+ ion and two IO3- ions are produced. So, the equilibrium expression can be written as:
Ksp = [Cu2+] * [IO3-]^2
Since the solubility of Cu(IO3)2 is given as 1.0 * 10^{-7}, we can represent the equilibrium concentrations as:
[Cu2+] = 1.0 * 10^{-7} M
[IO3-] = 2 * (1.0 * 10^{-7}) M = 2.0 * 10^{-7} M
Substituting these values into the equilibrium expression, we get:
Ksp = (1.0 * 10^{-7}) * (2.0 * 10^{-7})^2
Now, we can calculate the solubility product constant (Ksp):
Ksp = 4.0 * 10^{-21}
Therefore, the solubility of Cu(IO3)2 is 4.0 * 10^{-21} M.