e4) a rope applies a horizontal force of 190 N to pull a crate a distance of 2 m across the floor. A frictional force of 50N opposes this motion
a) what is the work done by the force applied by the rope?
b)what is the work done by the frictional force?
c)what is the total work done on the crate
To find the answers to these questions, we can use the formula for work:
Work = Force x Distance x cos(angle)
In this case, the angle between the force and the direction of motion is 0 degrees because the force and the displacement are in the same direction. Therefore, the cosine of 0 degrees is 1.
a) What is the work done by the force applied by the rope?
The force applied by the rope is 190 N, and the distance is 2 m. Using the formula, we have:
Work = 190 N x 2 m x cos(0°)
Work = 380 Nm (or Joules)
b) What is the work done by the frictional force?
The frictional force is 50 N, and the distance is 2 m. Using the formula, we have:
Work = 50 N x 2 m x cos(0°)
Work = 100 Nm (or Joules)
c) What is the total work done on the crate?
The total work done on the crate is the sum of the work done by the force applied by the rope and the work done by the frictional force.
Total Work = Work by rope force + Work by frictional force
Total Work = 380 Nm + 100 Nm
Total Work = 480 Nm (or Joules)