physics

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When a 58g tennis ball is served, it accelerates from rest to a speed of 45m/s. The impact with the racket gives the ball a constant acceleration over a distance of 44cm. What is the magnitude of the net force acting on the ball?

• physics -

Vf^2 = Vo^2 + 2a*d.
a = (Vf^2-Vo^2)/2d,
a = ((45)^2-0) / 0.88 = 2301 m/s^2.

Fn = ma = 0.058kg * 2301 = 133.5 N.

NOTE:

44 cm = 0.44 m.
58 g. = 0.058 kg.

• physics -

133.45

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