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how long is the diagonal of a piece of paper that is 8.5 in by 11in
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how long is the diagonal of a piece of paper that is 8.5 in by 11in
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it serves no purpose to post the same question multiple times.
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how long is the diagonal of a piece of paper that is 8.5 in by 11in
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what is sqrt(8.5^2+11^2)?
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The dimensions of a rectangular piece of paper are 8.5 inches and 11 inches.Veronica folded the piece of paper along its
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x^2 + x^2 = 10^2 2x^2 = 100 x^2 = 50 x = √50
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a rectangular piece of paper has length=14cm and breadth=12cm. A square piece of paper of perimeter 24 cm is cut off from it.
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the original area is 12*14 = 168 the square piece is 6x6, with area 36 I assume you can now solve
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Squares of side length x are removed from the 4 corners of an 11in by 8.5in piece of paper. The sides are then folded up to
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