an object was launched with the velocity of 20 m/s at an angle 45 degree to the vertical . at the top of its trajectory the object broke into two equal pieces.one piece fell vertically downward .where would the other piece fall?(g=10m/s^2)

Question

an object was launched with the velocity of 20 m/s at an angle 45 degree to the vertical . at the top of its trajectory the object broke into two equal pieces.one piece fell vertically downward .where would the other piece fall?(g=10m/s^2)

Answer 1

it i'll be 60m

as there is no external force acting except gravitational force ,do its path should be at the range of parabolic path

range(R)=u^2sin(theta)/g

here u=20,theta=45,g=10

thus R=20^2sin45/10=4

conservation of momentum m1d1+m2d2=md

m/2*20+m/2*d2=m40

d2=60

the other piece will fall 60m far from origin