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Find the volume of the solid generated by revolving the region bounded by y= 5 cosh (x) and y= 5 sinh (x) between x = 0 and x = 1 about the x-axis

  • Math -

    v = Int(pi*(R^2-r^2) dx) [0,1]
    where
    R = 5cosh(x)
    r = 5sinh(x)

    v = 5pi*Int(cosh(x) - sinh(x) dx) [0,1]
    = 5pi*(sinh(x)-cosh(x))[0,1]
    =5pi*[(sinh(1)-cosh(1))-(sinh(0)-cosh(0))
    = 5pi*(-1/e + 1)
    = 5pi(e-1)/e

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