In Exam Figure 7, AA′ = 33 m and BC =7.5 m. The span is divided into six equal parts at E, G,

C, I, and K. Find the length of A′B. Round your answer to two decimal places.

no figures here. 'splain pleez

imagine an isosclese triangle with the base being 33m (from angle A to angle A') and the right leg is 7.5 m long (BC) the span or width of the triangle is divided by 6 vertical lines with equal distances from eachother. so we need to find the length of the left leg AB...hope this helps, i need the anser too

In Exam Figure 7, AA′ = 33 m and BC =7.5 m. The span is divided into six equal parts at E, G,

C, I, and K. Find the length of A′B. Round your answer to two decimal places.

The length of A'B is '18.12'

For sure it's the right answer.

To find the length of A'B, we can start by calculating the length of each equal part of the span.

Given that the span is divided into six equal parts, we can find the length of each part by dividing the total length of BC by six.

BC = 7.5 m

Length of each part = BC / 6
= 7.5 m / 6
= 1.25 m

Now, we can determine the length of A'C. We know that AA' = 33 m, and since AE, EC, and A'C together make up the total length of AA', we can calculate the length of A'C by subtracting the sum of AE, EC, from AA'.

AE + EC = Length of each part * 2
= 1.25 m * 2
= 2.5 m

A'C = AA' - (AE + EC)
= 33 m - 2.5 m
= 30.5 m

Finally, we can find the length of A'B by subtracting the length of A'C from the total length of A'B.

A'B = A'C - BC
= 30.5 m - 7.5 m
= 23 m

Therefore, the length of A'B is 23 meters.